Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.4 - Solving Special Systems of Linear Equations - Exercises - Page 258: 33

Answer

The solutions are $x=-6$ and $x=−2$.

Work Step by Step

The given equation is $\Rightarrow |2x+6|=|x|$ Write related linear equations. $\Rightarrow 2x+6=x$ or $2x+6=−x$ Solve the first equation. $\Rightarrow 2x+6=x$ Add $-6-x$ to each side. $\Rightarrow 2x+6-6-x=x-6-x$ Simplify. $\Rightarrow x=-6$ Solve the second equation. $\Rightarrow 2x+6=-x$ Add $-6+x$ to each side. $\Rightarrow 2x+6-6+x=-x-6+x$ Simplify. $\Rightarrow 3x=-6$ Divide each side by $3$. $\Rightarrow \frac{3x}{3}=-\frac{6}{3}$ Simplify. $\Rightarrow x=-2$ Check $x=-6$ $\Rightarrow |2x+6|=|x|$ $\Rightarrow |2(-6)+6|=|-6|$ $\Rightarrow |-12+6|=|-6|$ $\Rightarrow |-6|=|-6|$ $\Rightarrow 6=6$ True. Check $x=-2$ $\Rightarrow |2x+6|=|x|$ $\Rightarrow |2(-2)+6|=|-2|$ $\Rightarrow |-4+6|=|-2|$ $\Rightarrow |2|=|-2|$ $\Rightarrow 2=2$ True. Hence, the solutions are $x=-6$ and $x=−2$.
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