Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.4 - Solving Special Systems of Linear Equations - Exercises - Page 258: 34

Answer

The solutions are $x=-5$ and $x=3$.

Work Step by Step

The given equation is $\Rightarrow |3x-45|=|12x|$ Write related linear equations. $\Rightarrow 3x-45=12x$ or $3x-45=−12x$ Solve the first equation. $\Rightarrow 3x-45=12x$ Subtract $3x$ from each side. $\Rightarrow 3x-45-3x=12x-3x$ Simplify. $\Rightarrow -45=9x$ Divide each side by $9$. $\Rightarrow \frac{-45}{9}=\frac{9x}{9}$ Simplify. $\Rightarrow -5=x$ Solve the second equation. $\Rightarrow 3x-45=-12x$ Subtract $3x$ from each side. $\Rightarrow 3x-45-3x=-12x-3x$ Simplify. $\Rightarrow -45=-15x$ Divide each side by $-15$. $\Rightarrow \frac{-45}{-15}=\frac{-15x}{-15}$ Simplify. $\Rightarrow 3=x$ Check $x=-5$ $\Rightarrow |3x-45|=|12x|$ $\Rightarrow |3(-5)-45|=|12(-5)|$ $\Rightarrow |-15-45|=|-60|$ $\Rightarrow |-60|=|-60|$ $\Rightarrow 60=60$ True. Check $x=3$ $\Rightarrow |3x-45|=|12x|$ $\Rightarrow |3(3)-45|=|12(3)|$ $\Rightarrow |9-45|=|36|$ $\Rightarrow |-36|=|36|$ $\Rightarrow 36=36$ True. Hence, the solutions are $x=-5$ and $x=3$.
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