Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.2 - Solving Systems of Linear Equations by Substitution - Exercises - Page 245: 16

Answer

The solution is $(0,2)$.

Work Step by Step

The given system of equations is $\Rightarrow 11x-7y=-14$ ...... (1) $\Rightarrow x-2y=-4$ ...... (2) Isolate $x$ in equation (2). $\Rightarrow x=-4+2y$ ...... (3) Substitute $-4+2y$ for $x$ in equation (1). $\Rightarrow 11(-4+2y)-7y=-14$ Use distributive property. $\Rightarrow -44+22y-7y=-14$ Add like terms. $\Rightarrow -44+15y=-14$ Add $44$ to each side. $\Rightarrow -44+15y+44=-14+44$ Simplify. $\Rightarrow 15y=30$ Divide each side by $15$. $\Rightarrow \frac{15y}{15}=\frac{30}{15}$ Simplify. $\Rightarrow y=2$ Substitute $2$ for $y$ in equation (3). $\Rightarrow x=-4+2(2)$ Simplify. $\Rightarrow x=-4+4$ $\Rightarrow x=0$ Check Equation (1) $\Rightarrow 11x-7y=-14$ $\Rightarrow 11(0)-7(2)=-14$ $\Rightarrow 0-14=-14$ $\Rightarrow -14=-14$ True. Check Equation (2) $\Rightarrow x-2y=-4$ $\Rightarrow 0-2(2)=-4$ $\Rightarrow -4=-4$ True. Hence, the solution is $(0,2)$.
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