Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.2 - Solving Systems of Linear Equations by Substitution - Exercises - Page 245: 15

Answer

The solution is $(5,-8)$.

Work Step by Step

The given system of equations is $\Rightarrow 5x+2y=9$ ...... (1) $\Rightarrow x+y=-3$ ...... (2) Isolate $x$ in equation (1). $\Rightarrow x=-3-y$ ...... (3) Substitute $-3-y$ for $x$ in equation (1). $\Rightarrow 5(-3-y)+2y=9$ Simplify. $\Rightarrow -15-5y+2y=9$ Add like terms. $\Rightarrow -15-3y=9$ Add $3y-9$ to each side. $\Rightarrow -15-3y+3y-9=9+3y-9$ Simplify. $\Rightarrow -24=3y$ Divide each side by $3$. $\Rightarrow \frac{-24}{3}=\frac{3y}{3}$ Simplify. $\Rightarrow -8=y$ Substitute $-8$ for $y$ in equation (3). $\Rightarrow x=-3-(-8)$ Simplify. $\Rightarrow x=-3+8$ $\Rightarrow x=5$ Check Equation (1) $\Rightarrow 5x+2y=9$ $\Rightarrow 5(5)+2(-8)=9$ $\Rightarrow 25-16=9$ $\Rightarrow 9=9$ True. Check Equation (2) $\Rightarrow x+y=-3$ $\Rightarrow 5-8=-3$ $\Rightarrow -3=-3$ True. Hence, the solution is $(5,-8)$.
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