Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.5 - Rewriting Equations and Formulas - Exercises - Page 40: 29

Answer

$b_2=\frac{2A}{h}-b_1$

Work Step by Step

The given formula is $\Rightarrow A=\frac{1}{2}h(b_1+b_2)$ Multiply each side by $2$. $\Rightarrow 2\cdot A=2\cdot \frac{1}{2}h(b_1+b_2)$ Simplify. $\Rightarrow 2 A=h(b_1+b_2)$ Divide each side by $h$. $\Rightarrow \frac{2A}{h}=\frac{h(b_1+b_2)}{h}$ Simplify. $\Rightarrow \frac{2A}{h}=b_1+b_2$ Subtract $b_1$ from each side. $\Rightarrow \frac{2A}{h}-b_1=b_1+b_2-b_1$ Simplify. $\Rightarrow \frac{2A}{h}-b_1=b_2$ Hence, the solution is $b_2=\frac{2A}{h}-b_1$.
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