Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.5 - Rewriting Equations and Formulas - Exercises - Page 40: 17

Answer

$x=\frac{y-6}{4+r}$, where $r\neq0$.

Work Step by Step

The given equation is $\Rightarrow y=4x+rx+6$ Subtract $6$ from each side. $\Rightarrow y-6=4x+rx+6-6$ Simplify. $\Rightarrow y-6=4x+rx$ Use distributive property. $\Rightarrow y-6=x(4+r)$ Divide each side by $4+r$. $\Rightarrow \frac{y-6}{4+r}=\frac{x(4+r)}{4+r}$ Simplify. $\Rightarrow \frac{y-6}{4+r}=x$ Hence, the rewritten literal equation is $x=\frac{y-6}{4+r}$, where $r\neq0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.