Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.5 - Rewriting Equations and Formulas - Exercises - Page 40: 18

Answer

$x=\frac{z-8}{6-p}$, where $p\neq0$.

Work Step by Step

The given equation is $\Rightarrow z=8+6x-px$ Subtract $8$ from each side. $\Rightarrow z-8=8+6x-px-8$ Simplify. $\Rightarrow z-8=6x-px$ Use distributive property. $\Rightarrow z-8=x(6-p)$ Divide each side by $6-p$. $\Rightarrow \frac{z-8}{6-p}=\frac{x(6-p)}{6-p}$ Simplify. $\Rightarrow \frac{z-8}{6-p}=x$ Hence, the rewritten literal equation is $x=\frac{z-8}{6-p}$, where $p\neq0$.
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