Answer
$(\frac{u\cdot v}{|v|^2})v$
Work Step by Step
$u\cdot v=|u||v|~cos~\theta$
$|u|~cos~\theta=\frac{u\cdot v}{|v|}$
The projection of $u$ onto $v$ is $(|u|~cos~\theta)\frac{v}{|v|}$
Then: $proj_vu=(\frac{u\cdot v}{|v|^2})v$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 5
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