Answer
$33.69^{\circ}$
Work Step by Step
We know that the angle between two vectors is:
$\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$
Therefore, $||u||=\sqrt{3^2+2^2}=\sqrt{13}$ and $||v||=\sqrt{4^2+0^2}=4$
$\theta =\cos^{-1} [ \dfrac{(3)(4)+(2)(0)}{ 4\sqrt {13}}]=\cos^{-1}[\dfrac{12}{4 \sqrt{13}}]$
So, $\theta =33.69^{\circ}$
