Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 19

Answer

$4\sqrt 5-1$ it is a scalar.

Work Step by Step

$||w||-1=\sqrt {w⋅w}-1=\sqrt {⟨−4,2⟩⋅⟨−4,2⟩}-1=\sqrt {-4(-4)+2(2)}-1=\sqrt {20}-1=4\sqrt 5-1$
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