Answer
$||u||=17$
Work Step by Step
$||u||=\sqrt {u⋅u}=\sqrt {⟨-8,15⟩⋅⟨−8,15⟩}=\sqrt {(-8)^2+15^2}=\sqrt {64+225}=\sqrt {289}=17$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 23
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