Answer
B = $45^{o}$
C = $90^{o}$
c = 1.41
Work Step by Step
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$
To solve the triangle, we need to find C, B, and c.
Finding B:
We can use the Law of Sines.
$\frac{1}{sin(45^{o})} = \frac{1}{sin(B^{o})}$
Therefore, B = $45^{o}$
Finding C:
Since we found 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$.
180 - 45 - 45 = 90
Therefore, C = $90^{o}$
Finding c:
We can use the Law of Sines.
$\frac{1}{sin(45^{o})} = \frac{c}{sin(90^{o})}$
Therefore, c = 1.41
In total:
B = $45^{o}$
C = $90^{o}$
c = 1.41