Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.1 - Law of Sines - 8.1 Exercise - Page 566: 23

Answer

B = $48.74^{o}$ C = $21.26^{o}$ c = 48.23

Work Step by Step

Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find B, C, and c. Finding B: We can use the Law of Sines. $\frac{125}{sin(110^{o})} = \frac{100}{sin(B^{o})}$ Therefore, B = $48.74^{o}$ Finding C: Since we found 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 110 - 48.74 = 21.26 Therefore, C = $21.26^{o}$ Finding c: We can use the Law of Sines. $\frac{125}{sin(110^{o})} = \frac{c}{sin(21.26^{o})}$ Therefore, c = 48.23 In total: B = $48.74^{o}$ C = $21.26^{o}$ c = 48.23
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