Answer
A = $48^{o}$
b = 2.29
c = 4.73
Work Step by Step
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$
To solve the triangle, we need to find b, c, and A.
Finding A:
Since we are given 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$.
180 - 28 - 104 = 48
Therefore, A = $48^{o}$
Finding b:
We can use the Law of Sines.
$\frac{b}{sin(28^{o})} = \frac{3.625}{sin(48^{o})}$
Therefore, b = 2.29
Finding c:
We can use the Law of Sines.
$\frac{c}{sin(104^{o})} = \frac{3.625}{sin(48^{o})}$
Therefore, c = 4.73
In total:
A = $48^{o}$
b = 2.29
c = 4.73
