Answer
The identity is verified.
$(sec~θ+tan~θ)(sec~θ-tan~θ)=1$
Work Step by Step
Use:
$1+tan^2θ=sec^2θ$
$1=sec^2θ-tan^2θ$
$(sec~θ+tan~θ)(sec~θ-tan~θ)=sec^2θ-tan^2θ=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 442: 47
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