Answer
$(x-5)^2+y^2=9$
Center: $(5,0)$
Radius: $r=3$
Work Step by Step
$x^2+y^2-10x+16=0$
Notice that $-10x=-2(5)x$ and that $5^2=25$
$x^2-10x+25-25+y^2+16=0$
$(x^2-10x+25)+y^2=25-16$
$(x-5)^2+y^2=9$
The equation of a circle in standard form:
$(x-h)^2+(y-k)^2=r^2$ in which $(h,k)$ is the center and $r$ is the radius
$(x-5)^2+(y-0)^2=3^2$
Center: $(5,0)$
Radius: $r=3$
