Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 347: 18

Answer

Center: $(-8,-1)$ Radius: $r=12$

Work Step by Step

The equation of a circle in standard form: $(x-h)^2+(y-k)^2=r^2$ in which $(h,k)$ is the center and $r$ is the radius $(x+8)^2+(y+1)^2=144$ $[x-(-8)]^2+[y-(-1)]^2=12^2$ Center: $(-8,-1)$ Radius: $r=12$
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