Answer
$\frac{x^2}{49}+\frac{y^2}{196}=1$
Work Step by Step
Major axis is vertical.
The point $(0,14)$ is a vertice:
$a=14$
The point $(-7,0)$ is one of the endpoints of the minor axis:
$b=7$
Standard form when major axis is vertical:
$\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$
$\frac{x^2}{7^2}+\frac{y^2}{14^2}=1$
$\frac{x^2}{49}+\frac{y^2}{196}=1$
