Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 338: 30

Answer

$x^2=14y$

Work Step by Step

The standard equation of a parabola with the given characteristics is: $x^2=4py$ Focus: $(0,p)=(0,3.5)$ $p=3.5$ So: $x^2=4(3.5)x$ $x^2=14y$
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