Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 338: 38

Answer

$\frac{x^2}{25}+\frac{y^2}{21}=1$

Work Step by Step

Major axis is horizontal. $(±2,0)=(±c,0)$ $c=2$ $2a=10$ $a=5$ $a^2=b^2+c^2$ $b^2=5^2-2^2=25-4=21$ $b=\sqrt {21}$ Standard form when major axis is horizontal: $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ $\frac{x^2}{5^2}+\frac{y^2}{(\sqrt {21})^2}=1$ $\frac{x^2}{25}+\frac{y^2}{21}=1$
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