Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 338: 37

Answer

$\frac{x^2}{49}+\frac{y^2}{24}=1$

Work Step by Step

Major axis is horizontal. $(±5,0)=(±c,0)$ $c=5$ $2a=14$ $a=7$ $a^2=b^2+c^2$ $b^2=7^2-5^2=49-25=24$ $b=2\sqrt {6}$ Standard form when major axis is horizontal: $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ $\frac{x^2}{7^2}+\frac{y^2}{(2\sqrt {6})^2}=1$ $\frac{x^2}{49}+\frac{y^2}{24}=1$
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