Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.6 - Combinations of Functions: Composite Functions - 2.6 Exercises - Page 221: 62c

Answer

$t=2.846~h$

Work Step by Step

$(N~o~T)(t)=90t^2+60t+600~~$ $1500=90t^2+60t+600~~$ $0=90t^2+60t-900~~$ (Divide both sides by 30) $0=3t^2+2t-30~~$ ($a=3,b=2,c=-30$): $t=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-2±\sqrt {2^2-4(3)(-30)}}{2(3)}=\frac{-2±\sqrt {364}}{6}$ Since $0\leq t\leq6$ $t=\frac{-2+\sqrt {364}}{6}\approx2.846$
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