Answer
$(N~o~T)(t)=90t^2+60t+600~~$, $0\leq t\leq6$
$N~o~T$ represents the number of bacteria in a refrigerated food as a function of time $t$ in hours.
Work Step by Step
$(N~o~T)(t)=N(3t+2)=10(3t+2)^2-20(3t+2)+600=10(9t^2+12t+4)-60t-40+600=90t^2+60t+600~~$, $0\leq t\leq6$