Answer
a), b) See graphs
Work Step by Step
We are given the functions:
$f(x)=\dfrac{1}{2}x$
$g(x)=x-4$
a) Determine $(f+g)(x)$
$(f+g)(x)=f(x)+g(x)=\dfrac{1}{2}x+x-4=\dfrac{3x-8}{2}$
Graph $f,g$ and $f+g$ on the same set of coordinate axes:
b) Determine $(f\circ g)(x)$:
$(f\circ g)(x)=f(g(x))=f(x-4)=\dfrac{x-4}{2}$
Graph $f,g$ and $f\circ g$ on the same set of coordinate axes: