Answer
$f(x)=\sqrt[3] x$
$g(x)=x^2-4$
Work Step by Step
$f(x)=\sqrt[3] x$
$g(x)=x^2-4$
$(f~o~g)(x)=f(g(x))=f(x^2-4)=\sqrt[3] {x^2-4}=h(x)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.6 - Combinations of Functions: Composite Functions - 2.6 Exercises - Page 220: 51
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