Answer
$f(x)=\frac{27x+6\sqrt[3] x}{10-27x}$
$g(x)=x^3$
Work Step by Step
$f(x)=\frac{27x+6\sqrt[3] x}{10-27x}$
$g(x)=x^3$
$(f~o~g)(x)=f(g(x))=f(x^3)=\frac{27x^3+6\sqrt[3] {x^3}}{10-27x^3}=\frac{27x^3+6x}{10-27x^3}=h(x)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.6 - Combinations of Functions: Composite Functions - 2.6 Exercises - Page 220: 56
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