Answer
$\frac{x^\frac{2}{3}-4}{x-8}$
Work Step by Step
$f(x)=x^\frac{2}{3}+1$
$\frac{f(x)-f(8)}{x-8}=\frac{(x^\frac{2}{3}+1) - (8^\frac{2}{3}+1)}{x-8}=\frac{x^\frac{2}{3}-4}{x-8}$
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