Answer
$\frac{-x-3}{9x^2}$
Work Step by Step
$\frac{g(x)-g(3)}{x-3}=\frac{(\frac{1}{x^2)})-(\frac{1}{3^2})}{x-3}=\frac{3^2-x^2}{(x-3)(9x^2)}=\frac{-x-3}{9x^2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 186: 77
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
