Answer
$2+h$
Work Step by Step
$\frac{f(2+h)-f(2)}{h}=\frac{((2+h)^2-2(2+h)+4)-(2^2-2(2)+4)}{h}=\frac{(4+4h+h^2-4-2h+4)-(4-4+4)}{h}=\frac{2h+h^2}{h}=2+h$
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