Answer
$\displaystyle \sum_{i=1}^{6}[1-(\frac{i}{6})^2]$
Work Step by Step
$[1-(\frac{1}{6})^2]+[1-(\frac{2}{6})^2]+...+[1-(\frac{6}{6})^2]=\displaystyle \sum_{i=1}^{6}[1-(\frac{i}{6})^2]$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 82
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