Answer
$\displaystyle \sum_{i=1}^{4}\frac{i!}{2^i}=\frac{13}{4}$
Work Step by Step
$\displaystyle \sum_{i=1}^{4}\frac{i!}{2^i}=\frac{1!}{2^1}+\frac{2!}{2^2}+\frac{3!}{2^3}+\frac{4!}{2^4}=\frac{1}{2}+\frac{2}{4}+\frac{6}{8}+\frac{24}{16}=\frac{1}{2}+\frac{1}{2}+\frac{3}{4}+\frac{3}{2}=\frac{13}{4}$
