Answer
$\frac{1}{4n^2+2n}$
Work Step by Step
$\frac{(2n-1)!}{(2n+1)!}=\frac{(2n-1)!}{(2n+1)(2n)(2n-1)!}=\frac{1}{(2n+1)(2n)}=\frac{1}{4n^2+2n}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 66
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