Answer
$$ -2\sqrt3$$
Work Step by Step
We know that $i=\sqrt{-1}$ and that $i^2=-1$. We also know that standard form is $a\pm bi$, where a and b are real numbers. Thus, simplifying the equation, we find:
$$ \sqrt6i\cdot \sqrt2i \\ \\ -\sqrt{12} \\ -2\sqrt3$$
