Answer
$\frac{13}{1+i}=\frac{13}{2}-\frac{13}{2}i$
Work Step by Step
$\frac{13}{1+i}=\frac{13}{1+i}\frac{1-i}{1-i}=\frac{13(1-i)}{(1-i)(1-i)}=\frac{13-13i}{1^2-i^2}=\frac{13-13i}{1+1}=\frac{13}{2}-\frac{13}{2}i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 119: 48
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