Answer
$\frac{6-7i}{1-2i}=4+i$
Work Step by Step
$\frac{6-7i}{1-2i}=\frac{6-7i}{1-2i}\frac{1+2i}{1+2i}=\frac{(6-7i)(1+2i)}{(1-2i)(1+2i)}=\frac{6+12i-7i-14i^2}{1^2-(2i)^2}=\frac{6+5i+14}{1+4}=\frac{20+5i}{5}=4+i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 119: 50
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