Answer
$\frac{8+16i}{2i}=8-4i$
Work Step by Step
$\frac{8+16i}{2i}=\frac{2(4)+2(8i)}{2(i)}=\frac{4+8i}{i}\frac{-i}{-i}=\frac{(4+8i)(-i)}{i(-i)}=\frac{-4i-8i^2}{-i^2}=\frac{-4i+8}{1}=8-4i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 119: 52
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