Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Cumulative Review - Page 678: 39

Answer

See below

Work Step by Step

Given $y^2+6x+4y+16=0$ Rewrite as: $(y^2+4y)+(6x+16)=00\\(y^2+4y+4)+(6x+12)=0\\(y+2)^2=-6(x+2)$ Where $(h,k)=(-2,-2)\\p=-\frac{3}{2}$ Compare the given equation to the standard form of an equation of a parabola.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.