Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Cumulative Review - Page 678: 3

Answer

$$x=7,\:x=5$$

Work Step by Step

Solving the equation using the rules of Algebra, we find: $$x_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:35}}{2\cdot \:1} \\ x=7,\:x=5$$
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