Answer
$$\frac{x^2+2x+41}{\left(x+5\right)\left(x-2\right)}$$
Work Step by Step
Creating like denominators, we find:
$$\frac{\left(x-3\right)\left(x-2\right)}{\left(x+5\right)\left(x-2\right)}+\frac{7\left(x+5\right)}{\left(x-2\right)\left(x+5\right)}\\ \frac{\left(x-3\right)\left(x-2\right)+7\left(x+5\right)}{\left(x+5\right)\left(x-2\right)}\\ \frac{x^2+2x+41}{\left(x+5\right)\left(x-2\right)}$$
