Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Cumulative Review - Page 678: 34

Answer

$$\left(-6,\:2\right)$$

Work Step by Step

Using the distance formula, we find: $$\sqrt{\left(-4-\left(-8\right)\right)^2+\left(-1-5\right)^2}\\ 2\sqrt{13}$$ Using the midpoint formula, we find: $$\left(\frac{-4-8}{2},\:\frac{-1+5}{2}\right)\\ \left(-6,\:2\right)$$
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