Answer
$Ir^2=a$.
Work Step by Step
Since they vary inversely, their product is constant, thus $Ir^2=a$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - Chapter Test - Page 607: 28
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