Answer
$$\frac{6x+18}{\left(x-3\right)\left(x+6\right)}$$
Work Step by Step
Ensuring that we have like denominators and then attempting to simplify, we find:
$$\frac{4\left(x+6\right)}{\left(x-3\right)\left(x+6\right)}+\frac{2\left(x-3\right)}{\left(x+6\right)\left(x-3\right)}\\ \frac{4\left(x+6\right)+2\left(x-3\right)}{\left(x-3\right)\left(x+6\right)}\\ \frac{6x+18}{\left(x-3\right)\left(x+6\right)}$$