Answer
$$\frac{1}{4y^3}$$
Work Step by Step
Performing the given operation and then factoring and combining like terms to simplify, we find:
$$\frac{3x^2y}{4x^3y^5}\times \frac{2xy^3}{6y^2}\\ \frac{xy}{3}\times \frac{3}{4y^4x}\\ \frac{y}{4y^4}\\ \frac{1}{4y^3}$$
