Answer
6
Work Step by Step
We use cross multiplication to solve. Doing this, we find: $$\left(x-2\right)\left(x+4\right)=\left(x-1\right)\left(x+2\right)\\ x^2+2x-8=x^2+x-2 \\ x=6$$ Checking, we see that the solution is not extraneous.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - Chapter Test - Page 607: 27
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