Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 50

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Given: $\log_2(x+1)=\log_8 3x\\\log_2(x+1)=\frac{\log_2 3x}{\log_2 8}\\\log_2(x+1)=\frac{\log_2 3x}{3}\\3\log_2(x+1)=\log_2 3x\\\log_2(x+1)^3=\log_23x\\(x+1)^3=3x\\x^3+3x^2+3x+1=3x\\x^3+3x^2+1=0\\x\approx-3.1038$