Answer
See below
Work Step by Step
Given: $10^{3x-8}=2^{5-x}\\3x-8=(5-x)\log(2)\\3x-8=5\log(2)-x\log(2)\\3x+x\log(2)=5\log(2)+8\\x(3+\log(2))=5\log(2)+8\\x=\frac{5\log(2)+8}{\log(2)+3}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 49
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
