Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 14

Answer

$\approx0.495$

Work Step by Step

$7^{3x}=18\\\log_7{(7^{3x})}=\log_718\\3x=\log_718\\x=\frac{\log_718}{3}\approx0.495$
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