Answer
$\frac{x^3-10x^2+33x-28}{x-5}=x^2-5x+8+\frac{12}{x-5}$
Work Step by Step
$\frac{x^3-10x^2+33x-28}{x-5}=x^2-5x+8+\frac{12}{x-5}$
Check: $(x-5)(x^2-5x+25)$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - Cumulative Review Chapters 1-6 - Page 474: 38
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