Answer
$$\left(3-7\right)+\left(4-2\right)i$$
Work Step by Step
We know that $i=\sqrt{-1}$. We also know that standard form is $a\pm bi$, where a and b are real numbers. Thus, simplifying the equation, we find:
$$\left(3-7\right)+\left(4-2\right)i \\ \left(3-7\right)+\left(4-2\right)i$$
