Answer
$$\left(x+3\right)^2+7$$
Work Step by Step
Completing the square to put the equation in vertex form, we find:
$$ x^2+6x+16+3^2-3^2 \\ \left(x+3\right)^2+16-3^2 \\ \left(x+3\right)^2+7 $$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - Cumulative Review Chapters 1-6 - Page 474: 28
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